Two days ago, Saturday, I posted four very nicely formatted abstract logic puzzles and challenged readers to try and solve them in the comments. Despite the overwhelming level of participation (1 person), no one posted the correct answers. Here are the answers then, as promised.

The way to look at these puzzles is as two separate sets of data – find the common feature of both sets, and then find the answer that matches both of those criteria. It’s very simple, you’ll see.

### Puzzle 1:

36 9 54 27 80 55 ? 70 25 Answer choices: 45 - 18 - 65 - 88 - 681

**Solution:**

In the vertical column of numbers here, it’s fairly simple to see that the numbers are multiples of 9 (or 3). So our solution will need to be a multiple of 9 (or 3), which leaves us with 45, 18, and 681. We can also easily see that the horizontal row is comprised of multiples of 5. The only multiple of both 9 AND 5 is 45.

### Puzzle 2:

25 61 78 23 ? 89 56 16 70 Answer choices: 28 - 52 - 93 - 45 - 34

**Solution:**

Here, it helps to consider these numbers as two separate digits, rather than a whole number. So if we then look at the horizontal row (7,8 ; 2,3 ; 8,9 ; 5,6) it’s easy to see that they’re sequential digits (8 is 1 more than 7, and so forth). There are two options that match this pattern: 45 and 34. It took me a while to find the pattern in the vertical set, but again we need to consider them as separate digits. And they all add up to 7. Of our two possible solutions, only one adds up to 7. 34.

### Puzzle 3:

OZT ZIR ? WZA ARZ ULL MUM TUU URO Answer choices: UUU - OTF - ZUT - RZP - PWA

**Solution:**

One letter is repeated throughout the horizontal set: Z. And again in the vertical set, there’s one repeated letter: U. So our solution will contain a Z and a U, therefore: ZUT.

### Puzzle 4:

ZED JTS KYX JIV ? NMT LKA HGC QIH Answer choices: UYD - UTS - BAQ - ESM - CPO

**Solution:**

This one is slightly more complicated. Take each of the vertical triplets, and chop off the first letter. We can see that the last two letters are in reverse alphabetical order. If we chop the last letter off the triplets in the horizontal set, we can see the first two letters are also in reverse alphabetical order. Combine those rules, and we can see the solution must be three letters in reverse alphabetical order. Therefore: UTS.

**Were you right? **

Were you way off?

Would you like to see more puzzles?

Let me know in the comments.

Were you way off?

Would you like to see more puzzles?

Let me know in the comments.